How can dlsym successfully import function from stripped binary library?
It's weird that dlsym can import functions from stripped binaries.
Can anyone tell me why/how?
=== FILE: a.c ===
int a1() { return 1; }
int a2() { return 2; }
=== end of a.c ===
=== FILE: b.c ===
#include <stdio.h>
#include <dlfcn.h>
#include <stdlib.h>
typedef int (*fint)();
fint dlsym_fint(void *handle, char *name)
{
fint x = (fint)dlsym(handle, name);
char *err = NULL;
if ((err = dlerror()) != NULL) {
printf("dlsym: %s\n", err);
exit(1);
}
return x;
}
int main()
{
void *dl = dlopen("a.so", RTLD_NOW);
fint a = NULL;
a = dlsym_fint(dl, "a1");
printf("%p: 开发者_高级运维%d\n", a, a());
a = dlsym_fint(dl, "a2");
printf("%p: %d\n", a, a());
return 0;
}
=== end of b.c ===
$ gcc -shared -fPIC -o a.so a.c
$ nm a.so
...
00000000000004ec T a1
00000000000004f7 T a2
...
$ strip a.so
$ nm a.so
nm: a.so: no symbols
$ gcc -o b b.c -ldl
$ ./b
0x2aaaaaac74ec: 1
0x2aaaaaac74f7: 2
Try readelf -s a.so
. The dynamic symbols are still there after that strip
.
(Or just switch to nm -D a.so
.)
strip
removes debugging symbol tables, not the dynamic symbol tables used by the dynamic linker. To remove those symbols as well, use -fvisibility=hidden
, and the symbol visibility function/variable attributes to select which functions you want to expose.
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