Multiple $(document).ready functions [duplicate]

This question already has answers here: jQue开发者_如何学Gory - multiple $(document).ready ...? (6 answers) Closed 9 years ago.

If I have multiple $(document).ready(...) functions, do they overwrite each other? For the sake of argument, pretend proper coding is thrown out the door on this one.

Say I have a $(document).ready(function() {...}); in my site's script file. Then I use a third party plugin that also uses $(document).ready(function() {...});. Will this overwrite my already created function or does jQuery "queue" these functions to all run when the document is ready?

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No, they do not override each other. Each function is executed.

You could of course check this easily yourself: http://jsfiddle.net/6jgGt/

Or understand from the jQuery code itself:

Line 255 is the ready function where the jQuery.bindReady(); is called which among other things initialises the readyList object on line 429 with readyList = jQuery._Deferred();

And once it's a deferred object the function passed in is appended with readyList.done( fn ); and we can see in the done method on line 41 that the element is added to an array with callbacks.push( elem ); so each one is saved separately...

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No, they don't overwrite each other. They are queued, like you said.