Mysql compare two tables
I have two tables in the same database with matching id's.
The first table is accounts
id - account_access - name - email - city - state - etc...
1 - 1 - Mark - mark@开发者_开发百科mark.com - Seattle - WA - blah,blah,blah
2 - 1 - Dave - dave@dave.com - Portland - OR - blah,blah,blah
3 - 0 - Jake - jake@jake.com - San Francisco - CA - blah,blah,blah
4 - 1 - Julie - julie@julie.com - Los Andeles - CA - blah,blah,blah
The second table is members
id - status - score - IQ
1 - 4 - 9000 - 108
2 - 5 - 8000 - 90
3 - 5 - 1000 - 25 (Disclaimer: Any relation to real people is purely coincidental)
4 - 5 - 5000 - 60
Since Jake wasn't very bright, he has zero access to the account.
What I want to know is how many people with account_access (1) have status (5), or how many people with status (5) have access.
I'm not familiar with how to word the SELECT statement comparing two tables, i would like to know number of rows and then to also retrieve the data to display.What you want to do is a left join.
SELECT count(*)
FROM Accounts
LEFT JOIN members
ON Accounts.id = members.id
WHERE status = 5
AND account_access = 1
Additional info on Left Joins: http://www.w3schools.com/sql/sql_join_left.asp
Select count(*) from accounts left join members using (id) where account access = 1 and status = 5;
I don't have the underscore in my bb, so you may have to substitute the space between account and access with an underscore before running the query.
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