Simple C code works fine on HPUX but segfaults on Linux. Why?
I have not done any serious C in a long, long time and would appreciate a quick explanation. The following code compiles and runs fine on HP/UX. It compiles without any warning on GCC 4.3.2 in Ubuntu (even with gcc -Wall), but segfaults when run on Linux.
Can anyone explain why?
#include <stdio.h>
int main() {
char *people[] = { "Abigail", "Bob" };
printf("First: '%s'\n", people[0]);
printf("Second: '%s'\n", people[1]);
/* this s开发者_StackOverflowegfaults on Linux but works OK on HP/UX */
people[1][0] = 'R';
printf("First: '%s'\n",people[0]);
return(0);
}
Your people array is in fact a char const *people[]
. Literal strings are typically in read-only memory on many systems. You can't write to them. Apparently, this is not the case on HP/UX.
The string literals are in a read-only data segment. Attempting to write to them is a segmentation violation.
You cannot modify string literals.
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