Dynamic drop down menu from Mysql Result set
I would like to create a dynamic menu from following result set.
Html structure should as follows,
<ul class="menu">
<li>Menu 1</li>
<ul class='submenu'>
<li>Submenu1</li>
<li>Submenu2</li>
</ul>
<li>Menu2</li>
<ul class='submenu'>
<li>Submenu1</li>
<li>Submenu2</li>
</ul>
<li>Menu 3</li>
</ul>
Tried as following,
<?php $cat = 0;?>
<?php foreach($this->submenus as $submenu): ?>
<?php if($cat!= $submenu->category_id): ?>
<li><?php echo $submenu->category_name ?></li>
<?php echo (!empty($submenu->subcategory_name))?'<ul>':''; ?>开发者_StackOverflow社区;
<?php $flag = $submenu->category_id; ?>
<?php endif;?>
<li class='sub'><?php echo $submenu->subcategory_name ?></li>
<?php if($cat!= $flag && $cat > 0): ?>
</ul>
<?php endif;?>
<?php $cat = $submenu->category_id;?>
<?php endforeach; ?>
It fails when close closing.
Please help.
Thanks
I have rearranged your PHP code a bit, please try the following:
<?php $cat = 0;?>
<?php $submenu_flag = 0;?>
<?php foreach($this->submenus as $submenu): ?>
<?php if($cat!= $submenu->category_id): ?>
<?php if($submenu_flag > 0): ?>
</ul>
<?php $submenu_flag = 0;?>
<?php endif;?>
<li><?php echo $submenu->category_name ?></li>
<?php if(!empty($submenu->subcategory_name)): ?>
<ul>
<?php $submenu_flag = 1; ?>
<?php endif;?>
<?php endif;?>
<?php echo (!empty($submenu->subcategory_name))?'<li class='sub'><?php echo $submenu->subcategory_name ?></li>':''; ?>
<?php $cat = $submenu->category_id;?>
<?php endforeach; ?>
you can use Accordion menu for this task.
See this link http://chandreshmaheshwari.wordpress.com/2011/05/27/accordian-menu/
Thanks.
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