Regular Expression to parse term out of URL

I'm in need of a regular express that will par开发者_JS百科se the first directory of a URL:

www.mydomain.com/find_this/anything/anything..

So -- I wasn't sure how to structure a regex to grab the string containing that first directory, any help appreciated.

Edit -- parsing is not an option, I am trying to create a regular expression.

Try this:

str = "www.mydomain.com/find_this/anything/anything"; 
path = /(?:http\:\/\/)?(?:www)?\.mydomain\.com\/([^\/]+)/.exec(str) [1]

You can just do:

var myString = "www.mydomain.com/find_this/anything/blah"
var string_I_want = myString.replace(/\/\//g, "").split("/")[1]

Much easier to read.

The stuff matched by the first capturing group (raw regex):

^(?:https?://)?(?:\w+)(\.\w+)*(?:\:\d+)/([^/]+)

Matches optional http:///https://, webserver/ip/port, then, the first group is what you want.

var url = 'www.mydomain.com/find_this/anything/anything';
var match = /^(?:https?:\/\/)?(?:\w+)(\.\w+)*(?:\:\d+)\/([^\/]+)/.exec(url);
var root = match[1];

Here are some options:

With capture:

/(.*?)/

With named capture:

/(?<first_directory>.*?)/

With protocol and capture:

(?:https?://.*?)?/(.*?)/

With protocol and named capture:

(?:https?://.*?)?/(?<first_directory>.*?)/

You'll just need to translate for your flavor.

Just try the following:

var rootDir = location.pathname.replace(/(^\/\w+\/).*/,"$1");