Nicer way to avoid moves/copies in C++0x
This question follows on from How to pass by lambda in C++0x?, but perhaps this is a clearer way to ask the question.
Consider the following code:
#include <iostream>
#define LAMBDA(x) [&] { return x; }
class A
{
public:
A() : i(42) {};
A(const A& a) : i(a.i) { std::cout << "Copy " << std::endl; }
A(A&& a) : i(a.i) { std::cout << "Move " << std::endl; }
int i;
};
template <class T>
class B
{
public:
B(const T& x_) : x(x_) {}
B(T&& x_) : x(std::move(x_)) {}
template <class LAMBDA_T>
B(LAMBDA_T&& f, decltype(f())* dummy = 0) : x(f()) {}
T x;
};
template <class T>
auto make_b_normal(T&& x) -> B<typename std::remove_const<typename std::remove_reference<T>::type>::type>
{
return B<typename std::remove_const<typename std::remove_reference<T>::type>::type>(std::forward<T>(x));
}
template <class LAMBDA_T>
auto make_b_macro_f(LAMBDA_T&& f) -> B<decltype(f())>
{
开发者_StackOverflow社区return B<decltype(f())>( std::forward<LAMBDA_T>(f) );
}
#define MAKE_B_MACRO(x) make_b_macro_f(LAMBDA(x))
int main()
{
std::cout << "Using standard function call" << std::endl;
auto y1 = make_b_normal(make_b_normal(make_b_normal(make_b_normal(A()))));
std::cout << "Using macro" << std::endl;
auto y2 = MAKE_B_MACRO(MAKE_B_MACRO(MAKE_B_MACRO(MAKE_B_MACRO(A()))));
std::cout << "End" << std::endl;
}
Which outputs the following:
Using standard function call
Move
Copy
Copy
Copy
Using macro
End
It is clear that the macro version somehow elides all move/copy constructor calls, but the function version does not.
I assume that there is a syntactically nice way of eliding all the moves and copies without lots of macros in C++0x, but I can't figure it out.
Reason:
I plan to use such code without moves or copies for building parameter packs, i.e.
auto y = (_blah = "hello", _blah2 = 4);
f(y, (_blah3 = "world", _blah4 = 67));
And have these not have no extra moves/copies compared to non parameter code.
You failed to provide a move constructor for B
. When that is provided, then on Visual Studio 2010 I get a bunch of moves. The reason that it doesn't ellide any of the moves is because you created a B<B<B<B<A>>>>
.
Compilers are still very immature w.r.t. move ellision. I would expect them to get better at it later.
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