Managing Oracle Synonyms
I was 开发者_Python百科reading this article: Managing Oracle Synonyms
Regarding the order of preference, when it come to resolving an object name to the actual object, it says:
Local objects will always be accessed first.
If a local object does not exist, the object with a private synonym will be accessed.
If a private synonym does not exist or the object does not exist, then the public synonym will be used.
I was wondering if the public objects are missing in this order somehow?
E.g. if user BOB queries
select * from FOOBAR
and there is no BOB.FOOBAR in dba_tables/views but PUBLIC.FOOBAR.
Does Oracle resolve it to PUBLIC.FOOBAR or will it check for synonyms first?
Thank you.
In your example, FOOBAR
is almost certainly a public synonym. There is no PUBLIC
schema but PUBLIC
is listed as the owner of a public synonym.
If I create a new public synonym
SQL> create public synonym pub_syn_emp
2 for scott.emp;
Synonym created.
the owner of that synonym ends up being PUBLIC
SQL> ed
Wrote file afiedt.buf
1 select object_name, owner, object_type
2 from dba_objects
3* where object_name = 'PUB_SYN_EMP'
SQL> /
OBJECT_NAME OWNER OBJECT_TYP
-------------------- ---------- ----------
PUB_SYN_EMP PUBLIC SYNONYM
In addition, item #3 does not appear to be correct. If there is a private synonym that points to a non-existent object and a public synonym that points to a valid object, the private synonym still takes precedence. You'll just get an error when Oracle tries to resolve the private synonym to an actual object.
SQL> create synonym syn_emp for scott.no_such_table;
Synonym created.
SQL> create public synonym syn_emp for scott.emp;
Synonym created.
SQL> select * from syn_emp;
select * from syn_emp
*
ERROR at line 1:
ORA-00980: synonym translation is no longer valid
At least up to 10g, PUBLIC is not a real user. You cannot create objects in the "Public schema":
SQL> CREATE TABLE public.foobar (id integer);
CREATE TABLE public.foobar (id integer)
ORA-00903: invalid table name
SQL> CREATE TABLE system.foobar (id integer);
Table created
SQL>
If you run this query:
SELECT object_name
FROM dba_objects
WHERE owner='PUBLIC'
AND object_type IN ('TABLE', 'VIEW');
You can answer the question about pre-defined tables/views in the PUBLIC "schema".
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