How To Not Have ALL Fields On An Edit View But Not Get The 'Overflow while converting to datetime.'
I am somewhat new to MVC 3 so this could be something simple. I have a Compact SQL 4 database. There is a Post object that has a Contents (string), Subject (string), When (DateTime) and Reposted (DateTime nullable) fields. During the Create's Post method, I manually force the When property to be DateTime.Now and it works great.
However, on my Edit View, I do NOT want to show this field or at least not let it be an editable field. When I do NOT put it as an editable field on the Edit View and they change say the Contents and then click Save I get the message:
An overflow occurred while converting to datetime.
During the Edit Postback, I am setting the Reposted field to DateTime.Now so it has to be the When field. When I debug on that postback I see that the "Post" object is only filled in with values of the fields I am displaying on the screen. So I decided to just grab the When field out with a LINQ query directly from the data but when I get to the 开发者_如何学CSaveChanges it fails and says the following:
An object with the same key already exists in the ObjectStateManager. The ObjectStateManager cannot track multiple objects with the same key
So how can I update an object and let the user only change a few pertinant fields? Seems like the Post object is not getting ALL of the existing values since they are not showing on the screen. How can I fill that object completely?
Edit: Here is the Post method.
[HttpPost]
public ActionResult Edit(Post post) {
if (ModelState.IsValid) {
db.Posts.Attach(post);
int Successes = 0;
int Failures = 0;
this.SendEMail(post, out Successes, out Failures);
post.Successes = Successes;
post.Failures = Failures;
post.Reposted = DateTime.Now;
db.ObjectStateManager.ChangeObjectState(post, EntityState.Modified);
db.SaveChanges();
return RedirectToAction("Index");
}
return View(post);
}
Include a hidden field in your view for the fields that you do not want to display e.g.
@Html.HiddenFor(model => model.When)
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