preg_match exact number

I'm using

$regex = '/'.implode('|', 10).'/i';    
preg_match($regex, $ids)

to find the number 10 in a list of IDs ($ids). However, if the list of IDs looks like this:

$ids = array(10, 110, 1010);

Would it bring back all of them? How can I make it find the exact number I am after, and not just find a number开发者_如何学Go that contains the number I'm after?

Thanks.

Edit:

I made a mistake above. The list of IDs is actually a string of comma separated values. For example:

$ids = "10,1010,101";

It's hard to explain the whole idea process behind this, but this is my full code:

<?php
$file  = fopen('allprods.csv', 'r');


$id = array($_GET['id']);    
$id = array_map('preg_quote', $id);
$regex = '/'.implode('|', $id).'/i';

$skus = array();
while (($line = fgetcsv($file)) !== FALSE) {  
    list($ids, $sku) = $line;

    if(preg_match($regex, $ids)) {
    $skus[] = $sku;
    }
}

$count = count($skus);
$i = 1;

echo $category_id;
foreach ($skus as $sku){
        echo $sku;
        if($i != $count) { echo "`"; }
        $i++;
}

I'm essentially rooting through a csv that has an ID column (some rows have multiple ids in that column, spearated by commas), and an sku column. More info here

So I need the code to check the string of ids for a certain ID, for example 10, and then add the appropriate SKU to an sku array.

I'm sure this code is a mess, so bear with me while I hack PHP to bits!

Edit: This is now solved! I used in_array instead, as mentioned in the answers. First of all I exploded the comma separate string. Code can be seen below:

$skus = array();
while (($line = fgetcsv($file)) !== FALSE) {  
    list($ids, $sku) = $line;

    $cats = explode(',',$ids);

    if (in_array($_GET['id'], $cats)) {
        $skus[] = $sku;
    }
}

Thanks for the help all.

Don't use a regex for this. Use in_array()

if( in_array(10, $ids) ) {
     // do something
}
else {
     // not found
}

In regex, if you want to find an exact match rather than just a substring match, you need to use start and end anchors. These are represented in regex by the ^ (start) and $ (end) characters.

So your regex to find "10" and not "110", etc, would be /^10$/.

But if you're looking for a number, why not just use == or in_array()?

PHP is quite capable of evaluating a numeric without having to parse it with regular expressions.

$regex = '/^10$/';

this will only match if the ^ is the beginning of the string, and the $ is the end of the string.

I'd use in_array() as suggested by @Cfreak, but if you want to use regex to match an id of 10 you can do

preg_match('/[^\d]?10[^\d]?/', implode('|', $ids))

If you have array(1,10,1010,010), implode() will change this to 1|10|1010|010 and the pattern will match against '10' not preceded or followed by any other digit (ie. another 0 or 1 as in 0101)