Matching a number and everything afterwards up until another number in Regex?

I've spent way too many minutes on this now, s开发者_JS百科o I thought I'd try my luck here instead.

I need a regex pattern that matches a whole number and everything afterwards up until another whole number appears. So in the following string:

50 !#!#€test30testtest 20!!!!`

it should match:

• 50 !#!#€test
• 30testtest
• 20!!!!

Is there a way to do that?

\d+\D+

does exactly that.

\d+ matches one or more digits, and \D+ matches one or more non-digits.

If you put each part in parentheses, you can then access the matches separately: (\d+)(\D+).

Try this: ([0-9]*[\D]*)

I tried it in rubular and here is the result for your test string:

http://rubular.com/r/qQiAbMlbQf

The following matches numbers and option all non-numbers after the number.

/[\d]+[^\d]*/