PHP Load Image if exist?

I am using this code for a slideshow:

<img src="<?php echo($array[0]); ?>"/>
<img src="<?php echo($array[1]); ?>"/>
<img src="<?php echo($array[2]); ?>"/>
<img src="<?php echo($array[3]); ?>"/>
<img src="<?php echo($array[4]); ?>"/>
<img src="<?php echo($array[5]); ?>"/>
<img src="<?php echo($array[6]); ?>"/>
<img src="<?php echo($array[7]); ?>"/>

I want to show imag开发者_运维百科es, only if they exist. Sometimes the $array has only 5 values.

How is this posible?

You should loop over the array values and echo an image tag for each value:

<?php
foreach($array as $img){
    echo '<img src="'.$img.'"/>'."\n";
}
?>

That's the perfect opportunity for a loop. You can either use a for loop (since your array is numerically indexed) or a foreach loop.

Using a for loop:

<?php $count = count($array); for($i = 0; $i < $count; $i++): ?>
  <img src="<?php echo($array[$i]); ?>" />
<?php endfor; ?>

In traditional syntax:

<?php $count = count($array); for($i = 0; $i < $count; $i++) { ?>
  <img src="<?php echo($array[$i]); ?>" />
<?php } ?>

Using a foreach loop:

<?php foreach($array as $img): ?>
  <img src="<?php echo $img; ?>" />
<?php endforeach; ?>

In traditional syntax:

<?php foreach($array as $img) { ?>
  <img src="<?php echo $img; ?>" />
<?php } ?>

Since this is a fairly basic question, I suggest you take the time to read the PHP Documentation chapter about control structures. There are essential. It is available here:

PHP Documentation: Control Structures

foreach($array as $src){ echo "<img src='$src' />"; }

<?php
foreach($array as $img){
    if(file_exists($img))
    echo '<img src="'.$img.'"/>'."\n";
}
?>

for($i=0;$i<count($array);$i++)
{
?>
  <img src="<?php echo($array[$i]); ?>"/>
<?php
}