If statements comparison integers

I have some if statements that read a variable from my mysql database and then echo out a number based on that variable. For some reason, the code below only echos out "1" and I dont know why. ($x is 670, but it still echos out 1)

CODE:

 //connect to database and assign $x a int from database
 if ($x<=100){
 echo 1;
 }

 if ($x>=500 && $x<1000){
 echo 2;
 开发者_运维技巧}

 if ($x>=1000 && $x<2500){
 echo 3;
 }

 if ($x>=2500 && $x<5000){
 echo 4;
  }

 if ($x>=5000 && $x<7500){
 echo 5;
 }

 if ($x>=7500  && $x<100000){
  echo 6;
 }

 if ($x>=10000){
 echo 7;
 }

EDIT: I did something stupid in my code with connecting to the DB. Thanks for your help anyway. I appreciate it.

It appears it's not the value you're expecting (int value of 670).

1. Less than or equal to 100? Yes: echo 1. This tells you that indeed the value is not an int value of 670.
2. The rest fail their boolean tests, as they don't pass those conditions.

To troubleshoot, try:

echo $x;

Perhaps explicitly cast that value as/after it comes out of your call to MySQL:

$x = (int)$x;

If this is indeed php, you $x surely is not 670.

See example here

Coudl you provide the code where you read x from the DB?

Try this:

    $x = $x + 0.0;

     if ($x<=100){
     echo 1;
     }

     if ($x>=500 && $x<1000){
     echo 2;
     }

     if ($x>=1000 && $x<2500){
     echo 3;
     }

     if ($x>=2500 && $x<5000){
     echo 4;
      }

     if ($x>=5000 && $x<7500){
     echo 5;
     }

     if ($x>=7500  && $x<100000){
      echo 6;
     }

     if ($x>=10000){
     echo 7;
     }