Regex for parsing parameters from url
I'm a total noob with regexes and although I was trying hard I cannot create proper regexes to perform the following operation :
- take url and check if it has a '
?
' followed by number with varying amount of digits. - if the match is correct, get the number after the '
?
' sign - exchange this number with different one.
So let's say we have this url :
http://website.com/avatars/avatar.png?56
we take '56
' and change it to '57
'.
I have the following regex for searching, I'm not sure if it's proper :
开发者_开发技巧\?[0-9]+
But I have no idea how to take ?
away. Should I just throw it away from the string and forget about using regex here ? Then the replace part is the only one left.
Try this:
var url = "http://website.com/avatars/avatar.png?56";
var match = url.match(/\?(\d+)/);
if(match != null) {
url = url.replace(match[1], "new number");
}
Your original regex will work just fine, just add back in the ?
you are taking out like so:
var newnum = 57;
url = url.replace(/\?[0-9]+/, '?'+ newnum);
I'm no regex expert but I think you can use a lookaround to ignore the '?'
(?<=?)([0-9]+)
which should give you your number in the first match
VERY dummied-down approach:
$('#parse').click(function(e){
var fromUrl = $('#from-url').val();
var newNum = parseInt($('#new-number').val(), 10);
var urlRE = /(?!\?)(\d+)$/;
if (urlRE.test(fromUrl)){
$('#result').text(fromUrl.replace(urlRE, newNum));
}else{
$('#result').text('Invalid URL');
}
});
DEMO
There are not extravagant check-sums, error-checking, etc. Fromt here, use window.location
or a string containing the URL if necessary.
Broken out in to a function (demo):
// Call this to replace the last digits with a new number within a url.
function replaceNumber(url, newNumber){
// regex to find (and replace) the numbers at the end.
var urlRE = /\?\d+$/;
// make sure the url end in a question mark (?) and
// any number of digits
if (urlRE.test(url)){
// replace the ?<number> with ?<newNumber>
return url.replace(urlRE, '?'+newNumber);
}
// invalid URL (per regex) just return same result
return url;
}
alert(replaceNumber('http://website.com/avatars/avatar.png?56', 57));
You could do this without regex.
var newNum = "57";
var url = "http://website.com/avatars/avatar.png?56";
var sUrl = url.split('?');
var rUrl = sUrl[0] + "?" + newNum;
alert(rUrl);
- Split the URL at the
?
- This returns an array.
- Add the first item in the array and the
?
and the new number back together.
http://jsfiddle.net/jasongennaro/7dMur/
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