Sql Inner Join with Two Conditions on Same Field

table_a:

id        label
-----------------
1         l1
2         l2
3         l3

table_b:

table_a_id      table_c_id
---------------------------
1               1
1               3
1               4
2               2
2               4
3               1
3               4
3               8

How can I select all records from table_a that are associated with both table_c_id 1 AND 4? Is it possible to have n table_c_id conditions?

The following is wrong, but it illustrates what is needed.

SELECT table_a.* 
 FROM table_a
 JOIN table_b ON ( table_a_id = id 
               AND table_c_id = 1
               AND table_c_id = 4 )

Use an IN clause.

EDIT: Updated the query based on the comments posted.

SELECT a.* 
      FROM table_a a INNER JOIN
            (
            SELECT table_a_id
               FROM table_b
            WHERE table_c_id IN(1,4)
                GROUP BY  table_a_id 
               HAVING COUNT(DISTINCT table_c_id) > 1
                --HAVING COUNT(1) > 1 --This scenario will not address repeating table_c_id's
        ) b 
ON a.id = b.table_a_id          

If I understand correctly, you want:

SELECT a.* 
  FROM table_a a
  JOIN (SELECT t.table_a_id
          FROM table_b t
         WHERE t.table_c_id IN (1, 4) 
      GROUP BY t.table_a_id
        HAVING COUNT(DISTINCT t.table_c_id) = 2) b ON b.table_a_id = a.id 

To get matching table_a rows which are associated to table_c's 1 & 4 as a pair.

SELECT a.* , b.table_c_id
FROM table_b b
LEFT JOIN table_a a ON table_a_id = a.id
WHERE b.table_c_id =1
OR b.table_c_id =4