if condition for huge amount of object properties

I have to show the record from database if at least one filed is filled with value out of 50 fields for a row.

I fetched data from database successfully. Stored in array of object like this

$obj[0]->prop1;
$obj[0]->prop2;

$obj[1]->prop1;
$obj[1]->prop2;

There are more than 50 properties for a object.

I have to check each property if one of them is not empty show that record.

I have a long if like this

if ($obj[$counter]->prop1 !='' || $开发者_如何学Goobj[0]->prop2 !='' ...
echo "show record"

wanted to know if there is shorten way. let me know if anything is not clear

Declare a function isEmpty() in the class. For each instance, you will have to only call

if(!($obj[$counter]->isEmpty()) {

   ...

}

I guess it's better to alter your query:

select f1, f2, ... f50, f1||f2...||f50 as fsum from ...

and then you can check if $obj[51] != ''

this will perform faster than php code...

No, you have to check each property individually...

So I found the easy way myself. You can just do a type cast the object to an array and check that array for values like this

foreach ((array)$data[$counter] as $value)
{
   if($value !='')
   {
      $addRec=true;
   }
}