using read to get input from a file or standard input doesn't store the read values [duplicate]

This question already has an answer here: While Do loop and variables in a bash script? (1 answer) Closed 2 years ago.

I'm trying to use the bash builtin read to read data from a file or from standard input (doesn't matter which for the purpose of the discussion, as long as I can pipe it in), and store them in an array. Thi开发者_JAVA技巧s sometimes works and sometimes not, and I'm not sure why.

Here is the test case:

values=(1 2 3)
echo "4 5 6" | read -a values; echo "${values[*]}"

The output should be "4 5 6", but instead its "1 2 3". On the other hand, when running it like this:

values=(1 2 3)
echo "4 5 6" | ( read -a values; echo "${values[*]}" )

I get the correct output.

Any ideas?

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BASH FAQ entry #24: "I set variables in a loop. Why do they suddenly disappear after the loop terminates? Or, why can't I pipe data to read?"

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Here is my solution (after figuring out that the question was stupid - thanks to Ignacio):

IFS="$(printf "\a")" read -ra values < <(some-command | tr '\n' '\a')

The problem is that Bash's process substitution (<()) strips out the new lines in the output (something about parameter expansion? I'm not sure) so I can't use "\n" as the record separator. So instead I translate the new-line characters in the command output into the "audible bell" character (which I don't expect to find any output with this in it) and use that as the record separator. In the end I get 1 line in each of values elements.