Converting a uint8_t array to an NSString

How can I affect a uint8_t array (see decryptedBuffer below) to an NSString?

uint8_t *decryptedBuffer;

NSString *cle2=[NSString stringWithUTF8String:decryptedBuffer];

NSString *str2=[player.name AES256Decrypt开发者_如何学GoWithKey:cle2]; 
NSLog(str2);


free(plainBuffer);
free(cipherBuffer);
free(decryptedBuffer);

uint8_t * is just a byte string which is compatible with char *, so you should just be able to pass the casted pointer to stringWithUTF8String, assuming the decrypted string is UTF-8 and it is NULL terminated:

NSString *s = [NSString stringWithUTF8String:(char *)decryptedBuffer];

If the data is not NULL terminated, you can use this:

NSString *s = [[[NSString alloc] initWithBytes:decryptedBuffer
                                 length:length_of_buffer
                                 encoding:NSUTF8StringEncoding] autorelease];

decryptedBuffer is an int (uint8_t), NSString stringWithUTF8String only works on strings, not ints. I think I found what you need: http://lists.apple.com/archives/cocoa-dev/2004/Apr/msg01437.html

That person used this syntax:

    NSString *theDigitsIWant = [[NSNumber numberWithInt:x] stringValue];

So you should do this:

    NSString *cle2 = [[NSNumber numberWithInt:decryptedBuffer] stringValue];