Template Return Types / Cast as function of Template
I'm working with some generated classes with broken polymorphism. For every generated class T, there are a handful of T_type_info, T_writer, T_reader classes which are only related to T conceptually.
What I'm trying to do is something like this:
template <class T> class Wrapper
{
public:
template <class W> W topic_cast(BrokenBaseClassWriter* p);
// other operations with the same problem ...
};
template <> class Wrapper<MyTopic>
{
public:
template <> MyTopicWriter* topic_cast(BrokenBaseClassWriter* p) { ... }
};
So that I can do things like:
void Write(const Wrapper<T>& topic)
{
BrokenBaseClassWriter p = not_important;
topic.topic_cast(p)->do_stuff();
}
My T classes are generated from an IDL and are concepts that exist in application space. They don't derive from anything. In my example above, W is not really an independent parameter, it's "Something Not T that depends on T". I'm trying to keep all knowledge of T in the app, and all knowledge of T' (withou开发者_Go百科t knowing about T) in the backend.
The compiler however says my topic_cast function is not a template function - I think because the template occurs in the return type and it wouldn't be distinguishable from any other instantiations. I know that that (templates differ only by return type) is not legal. Only in my case it really would be unique because W is not an independent parameter. But arguing with the compiler is seldom helpful.
Can I do this, or is there another way to do this "cast as function of template type"?
Could this not be achieved with a traits system?
template <typename T> struct my_traits
{
};
template <> struct my_traits<MyClass>
{
typedef MyWriter writer_type;
};
template <typename T> struct Wrapper
{
typename my_traits<T>::writer_type topic_cast();
};
This can't work:
topic.topic_cast(p)->do_stuff();
Because the compiler can not deduce the return type.
So you have to explicitly tell the compiler what return type you want:
topic.topic_cast<MyType>(p)->do_stuff();
The implementation you provide is for a specific type.
So when you use that specific type that code will be produced:
topic.topic_cast<MyTopicWriter>(p)->do_stuff(); // Use the explicit specialization
This compiles with gcc:
class BrokenBaseClassWriter;
class MyTopic;
class MyTopicWriter;
template <class T> class Wrapper
{
public:
template <class W> W *topic_cast(BrokenBaseClassWriter* p);
// other operations with the same problem ...
};
template <> template<>
MyTopicWriter *Wrapper<MyTopic>::topic_cast<MyTopicWriter>(BrokenBaseClassWriter* p)
{
return 0;
}
int main(int argc, int argv)
{
BrokenBaseClassWriter* p = NULL;
Wrapper<MyTopic> caster;
MyTopicWriter *casted = caster.topic_cast<MyTopicWriter>(p);
}
Of course, it still exposes MyTopicWriter in your main code...
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