Get last several nodes in XSL, spanning parents

I have XML that looks like this:

<2011>
  <开发者_StackOverflow社区;05>
    (item)
    (item)
  </05>
  <06>
    (item)
  </06>
</2011>

I'd like to get the last three items. However, I can't just get the last three items of the last item in the list, because sometimes that last item doesn't have three (in this example, it's if we're in a new month and there's only one item posted so far).

How do I go about getting the last three items without worrying about which parent they belong to?

This is the XSLT I was speaking about, assuming the @polishchuk input:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

 <xsl:template match="/">
     <xsl:copy-of select="(/*/*/*)[position()>last()-3]"/>
 </xsl:template>

</xsl:stylesheet>