Parse error: syntax error, unexpected T_STRING on line 26 [closed]

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Hello im having an issue with my code:

<?php

s开发者_StackOverflowession_start();

$host="localhost"; 
$username="root"; 
$password="power1"; 
$db_name="members"; 
$tbl_name="users";

$link  = mysql_connect($host, $username, $password)or die("cannot connect. Please contact us");
mysql_select_db($db_name)or die("cannot select DB. Please contact us");

$queryString = $_SERVER['QUERY_STRING'];

$uemail = $_SESSION['$queryString'];

$query = "SELECT * FROM users WHERE email='$uemail'";

$result = mysql_query($query) or die(mysql_error());

while($row = mysql_fetch_array($result)){

if ($queryString == $row[activationkey]){

   echo "Congratulations! You have succesfully activated you account. You may now login.";

   $sql=("UPDATE users SET activationkey='' AND status='activated' WHERE username=".$row['username']);

   if (!mysql_query($sql))

{

    die('Error: ' . mysql_error());

}

    }

        }
?>

What do you think the issue is? Thanks

---

You are not closing a quote here:

$query = "SELECT * FROM users WHERE email=$uemail;

Replace it with:

$query = "SELECT * FROM users WHERE email='$uemail'";

---

$query = "SELECT * FROM users WHERE email=$uemail;

There is a double quote missing

$query = "SELECT * FROM users WHERE email='$uemail'";

Remember to escape all your parameters used in your sql statements!

---

You forgot to terminate this line with a quote

$query = "SELECT * FROM users WHERE email=$uemail;

---

$query = "SELECT * FROM users WHERE email='".$uemail."'";
$sql = ("UPDATE users SET activationkey='' AND status='activated' WHERE username='".$row['username']."'");

Remember to put single ' or double " quotes at start and end of the val where datatype is varchar