PHP - Display No Code if PHP Value is Empty

I am using queries like this to pull in information from a database:

<p><strong>Show Description:</strong><br/><?php echo cimy_uef_sanitize_content(get_cimyFieldValue(1, 'show-description')); ?></p>

Is there any way to put the title 开发者_如何转开发(Show Description) into the PHP string and then, if the PHP field value is empty, to not show anything?

I think it would involve a PHP if/else statement, but I am not sure what the code should look like.

Thanks Zach

It is hard without seeing the code for those functions, but at a guess:

if (get_cimyFieldValue(1, 'show-description') != '')
    {
    echo "<p><strong>Show Description:</strong></p>" . cimy_uef_sanitize_content(get_cimyFieldValue(1, 'show-description'));
    }

Should work

You can use PHP's empty() function for this purpose -

<p>
    <?php 
        $data = cimy_uef_sanitize_content(get_cimyFieldValue(1, 'show-description')); 

        if( !empty($data) )
        {
            echo "<strong>Show Description:</strong><br/>";
            echo $data;
        }
    ?>
</p>

According to the documentation, this function will return true if the $data variable is either -

1. "" (an empty string)
2. 0 (0 as an integer)
3. 0.0 (0 as a float)
4. "0" (0 as a string)
5. NULL
6. FALSE
7. array() (an empty array)
8. var $var; (a variable declared, but without a value in a class)

If I understood You correctly, You need something like this:

<?php $title = cimy_uef_sanitize_content(get_cimyFieldValue(1, 'show-description')); ?>
<?php if(!empty($title)): ?>
<p>
    <strong>Show Description:</strong><br/>
    <?php echo $title; ?>
</p>
<?php endif; ?>

Not compiled, so there can be errors in code, but you get the point...