$(this).serialize() -- How to add a value?

currently I have the following:

$.ajax({
    type: 'POST',
    url: this.action,
    data: $(this).serialize(),
});

This works fine, however I would like to add a value to data, so I tried

$.ajax({
    type: 'POST',
    url: this.action,
    d开发者_StackOverflowata: $(this).serialize() + '&=NonFormValue' + NonFormValue,
});

But that didn't post correctly. Any ideas on how you can add an item to the serialize string? This is a global page variable that isn't form specific.

While matt b's answer will work, you can also use .serializeArray() to get an array from the form data, modify it, and use jQuery.param() to convert it to a url-encoded form. This way, jQuery handles the serialisation of your extra data for you.

var data = $(this).serializeArray(); // convert form to array
data.push({name: "NonFormValue", value: NonFormValue});
$.ajax({
    type: 'POST',
    url: this.action,
    data: $.param(data),
});

Instead of

 data: $(this).serialize() + '&=NonFormValue' + NonFormValue,

you probably want

 data: $(this).serialize() + '&NonFormValue=' + NonFormValue,

You should be careful to URL-encode the value of NonFormValue if it might contain any special characters.

Don't forget you can always do:

<input type="hidden" name="NonFormName" value="NonFormValue" />

in your actual form, which may be better for your code depending on the case.

firstly shouldn't

data: $(this).serialize() + '&=NonFormValue' + NonFormValue,

be

data: $(this).serialize() + '&NonFormValue=' + NonFormValue,

and secondly you can use

url: this.action + '?NonFormValue=' + NonFormValue,

or if the action already contains any parameters

url: this.action + '&NonFormValue=' + NonFormValue,

Add the item first and then serialize:

$.ajax({
    type: 'POST',
    url: this.action,
    data: $.extend($(this), {'NonFormValue': NonFormValue}).serialize()
});

We can do like:

data = $form.serialize() + "&foo=bar";

For example:

var userData = localStorage.getItem("userFormSerializeData");
var userId = localStorage.getItem("userId");

$.ajax({
    type: "POST",
    url: postUrl,
    data: $(form).serialize() + "&" + userData + "&userId=" + userId,
    dataType: 'json',
    success: function (response) {
        //do something
    }
});

this better:

data: [$(this).serialize(),$.param({NonFormValue: NonFormValue})].join('&')

You can write an extra function to process form data and you should add your nonform data as the data valu in the form.seethe example :

<form method="POST" id="add-form">
    <div class="form-group required ">
        <label for="key">Enter key</label>
        <input type="text" name="key" id="key"  data-nonformdata="hai"/>
    </div>
    <div class="form-group required ">
        <label for="name">Ente Name</label>
        <input type="text" name="name" id="name"  data-nonformdata="hello"/>
    </div>
    <input type="submit" id="add-formdata-btn" value="submit">
</form>

Then add this jquery for form processing

<script>
$(document).onready(function(){
    $('#add-form').submit(function(event){
        event.preventDefault();
        var formData = $("form").serializeArray();
        formData = processFormData(formData);
        // write further code here---->
    });
});
processFormData(formData)
{
    var data = formData;
    data.forEach(function(object){
        $('#add-form input').each(function(){
            if(this.name == object.name){
                var nonformData = $(this).data("nonformdata");
                formData.push({name:this.name,value:nonformData});
            }
        });
    });
    return formData;
}