开发者

Extjs store.on('save', afterSave(resp));

I have a simple ExtJs (3.4) Grid with a Writer. When the user makes some changes the store is saved to the server as follows:

store.on('save', afterSave(resp));

开发者_JAVA技巧All is fine. However, I want to get a response as to wheather the record has been saved successfully, failed or an update conflict happed. How to best do this?


Are you using Ext.data.proxy.Ajax to load your stores? If so, you can use the reader property to evaluate and handle the server responses.

Another option would be to make AJAX called directly and handle the responses from there as well


I used exception listener to parse the data as suggested here. But, is this the right way to do this.

Ext.data.DataProxy.addListener('exception', function(proxy, type, action,
options, res) {
if (type == 'response') {
var success = Ext.util.JSON.decode(res.responseText).success;
if (success) {
console.log('UPDATE OK');
} else {
console.log('UPDATE FAILED');
}
}
});
0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜