Problem in getting url.getContent()
I have a problem in my hand.
I have a URL, And when i initiate the connect to this url and execute url.getContent().
The response is of type sun.net.www.protocol.http.HttpURLConnection$HttpInputStream
I tried to assign the output to HttpURLConnectionHttpInputStream h = url.getContent()
. But i was unsuccessful.
I imported corresponding libraries to code, but still no luck.
If i inspect the url.getContent() in eclipse, it also shows the variable thei$0 in it.
All i need is a URL in this$0. But till now i am unable to retreive it.
In this$0 there is a variable names url and i am trying to fetch it.
I also have hard time understand this$0 and hoe to retrieve it.
After using the stre开发者_C百科ams i get some non readable output
Regards Dheeraj Joshi
You should use the openStream method of the url class.
Code snippet:
InputStream in = url.openStream();
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
String line = reader.readLine();
If the output is not in a readable string format, then use:
InputStream in = url.openStream();
byte[] buffer = new byte[512];
int bytesRead = in.read(buffer);
I found the answer.
The problem statement: When i execute a URL the response had another URL in it and i needed to fetch it.
Solution:
java.net.URLConnection urlconn = url.openConnection();
java.net.HttpURLConnection conn = (java.net.HttpURLConnection)urlconn;
conn.connect();
conn.getContent();
URL newurl = conn.getURL();
System.out.println(newurl.toString());
The response can be get using getContent() and. The connection object will have a delegate with the new URL. The new URL can be fetched using getURL method.
Regards
Dheeraj Joshi
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