开发者

Debugging parser generated code

I have generated a parser code using Lemon Parser. I am not able to debug the generated code. Control shows some other source code than the currently executing statement. Breakpoints are dis开发者_StackOverflow中文版placed. I tried on gdb and Visual C++. Both have the same problem. Please tell me the way to debug it.


Let's say your input file is named mylexer.y in which case Lemon will generate myparser.c and myparser.h

Inside of myparser.c you will see lines such as this

#line 1 "myparser.y"

These are line directives. They are good for tracing syntax errors back to the file that was used to generate the code. They are not good for debugging.

To suppress them invoke Lemon with the -l option.

lemon -l myparser.y

To see other options not mentioned in the documentation use -?

lemon -?


The following is a certified WAG (Wild Ass Guess):

I would recommend looking at all of the macros being used by the parser generator and see if there are any escaped newlines in them. If there are, try removing all of them (by joining the lines together) and then recompile the file. Then looked at the code in the debugger -- things suddenly may be back to where they should be.

Backstory: Back in the 80's I developed and marketed a debugger called CDB. As I ported it to anything that had U*NX in it's name I became intimately familiar with the idiosyncrasies of the various compilers and how they emitted debug info in certain situations.

One widespread problem had to do with macros that had escaped newlines them. E.g.

#define foo(bar) bar + \
    snort + something_else

x = foo(5);
y = 2;

If the line number for y = 2; should have been 5, many symbol tables would end up showing it as 6, and every line after it would be off-by-one. And each use of such a macro would throw the line numbers farther and farther off.


Check optimization, debug information options if you are building them as lib/dll.

0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜