Does STL or BOOST provide any clean way to get the sort order without reordering original sequence?
I'd like to find the sort order of a vector, for example, without reordering the vector.
I can think of several ways to do this, I'm wondering if I'm missing some built-in STL or BOOST way to do this.
I imagine if the functionality were available the code would end up looking something like this:
std::vector<float> unsortedSeq;
unsortedSeq.pu开发者_如何学运维sh_back( 1.1 );
unsortedSeq.push_back( 1.0 );
unsortedSeq.push_back( 0.5 );
unsortedSeq.push_back( 1.2 );
unsortedSeq.push_back( 1.15 );
std::list<std::size_t> sortOrder;
std::sort_indices( unsortedSeq.begin(), unsortedSeq.end(), sortOrder.begin() );
BOOST_FOREACH( std::size_t index, sortOrder )
{
std::cout << index << "\n"
}
2
1
0
4
3
Anyone know any STL or BOOST-sims that would do what I'm asking about as simply as shown?
std::vector<float> v;
// filled somewhere else
std::vector<std::size_t> indices(v.size());
// iota is from <numeric>, C++0x
std::iota(indices.begin(), indices.end(), 0);
std::sort(indices.begin(), indices.end(), [&v](std::size_t left, std::size_t right)
{
return v[left] < v[right];
});
You would do something like this:
template<typename T>
class SortOrder
{
public:
SortOrder(const std::vector<T> *_sortArray) : sortArray(_sortArray) {;}
bool operator()(int lhs, int rhs) const
{
return sortArray[lhs] < sortArray[rhs];
}
private:
const std::vector<T> *sortArray;
};
//To do the sorting:
#include <boost/range/counting_range.hpp>
auto countRange = boost::range::counting_range(0, myListOfStuff.size());
//Build a vector<int> that has one index for every value in your actual vector.
vector<int> indexList(countRange.begin(), countRange.end());
std::sort(indexList.begin(), indexList.end(), SortOrder(&myListOfStuff));
This generates a vector of indices, and then sorts them based on the vector of actual stuff.
No; you have to do it yourself.
Fortunately, it's quite easy! (which may be why it's not provided)
- Consider input vector
v
- Create a vector of indexes 0..n, where
n
is the size of your inputv
std::sort
the vector of indexes, providing a reference to the inputv
, and a custom comparator that returnsv[left] < v[right]
.
Another example, using boost::ref
...
#include <algorithm>
#include <iostream>
#include <vector>
#include <iterator>
#include <boost/ref.hpp>
int main()
{
int n[] = { 3, 4, 1, 7, 10 };
std::vector<int> v(n, n + 5);
// print the original sequence
std::copy(v.begin(), v.end(), std::ostream_iterator<int>(std::cout, " "));
std::cout << std::endl;
// fill another vector with references to the data in the original
std::vector<boost::reference_wrapper<int> > vp;
std::transform(v.begin(), v.end(), std::back_inserter(vp), &boost::ref<int>);
// sort the references
std::sort(vp.begin(), vp.end());
// print the filtered version.
std::copy(vp.begin(), vp.end(), std::ostream_iterator<int>(std::cout, " "));
std::cout << std::endl;
// print the original sequence again to show it hasnt changed
std::copy(v.begin(), v.end(), std::ostream_iterator<int>(std::cout, " "));
std::cout << std::endl;
}
With just a few modifications to Nicol Bolas' answer, this allows any random access iterator to be used as input (as long as it is a random iterator and has a reference
type member).
The comparison function could also be provided (just like in std::sort
, the default being std::less).
template<typename const_iterator>
class SortOrder
{
public:
using Compare = std::function<bool(typename const_iterator::reference, typename const_iterator::reference)>;
SortOrder(const_iterator to_sort, Compare comp = std::less<typename const_iterator::reference>()) :
to_sort_(to_sort),
comp_(comp)
{}
bool operator()(int lhs, int rhs) const
{
return comp_(*(to_sort_ + lhs), *(to_sort_ + rhs));
}
private:
const_iterator to_sort_;
Compare comp_;
};
vector<double> to_sort{1, 5, 9, 2, 6, 17, 2, 8.5};
// Create integers, one value for each to_sort element
auto count_range = boost::counting_range(size_t(0), to_sort.size());
vector<int> indices(count_range.begin(), count_range.end());
// indices = 0 1 2 3 4 5 6 7
auto it = to_sort.begin();
sort(indices.begin(), indices.end(), SortOrder<decltype(it)>(it));
// indices = 0 3 6 1 4 7 2 5
A working example could be find here.
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