error on mysql_num_rows
my code is following iam getting a error on "Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource..." help me to solve this
<?php
$type = $_REQUEST['type'];
#defauts
$maxRows_p = 10;
$pageNum_p = 0;
if (isset($_GET['pageNum_p'])) {
$pageNum_p = $_GET['pageNum_p'];
}
$startRow_p = $pageNum_p * $maxRows_p;
$limit = ' LIMIT '.$startRow_p.', '.$maxRows_p;
//BUILD Addition Search Conditions
if(isset($_REQUEST['district']) && ($_REQUEST['district'] != 'All'))
$search = ' district = '.$_REQUEST['district'];
if(isset($_REQUEST['city']) && ($_REQUEST['city'] != 'All'))
$search = ' city = '.$_REQUEST['city'];
$search= ' availibility = "0" ';
$searchStr = @implode(' and ',$search);
$sql = 'select * FROM properties WHERE type= "'.$type.'" and ';
$sql .= $searchStr;
## DEBUGi
//if($debugP) echo 'Zip Code Radius SQL<hr>'.$sql;
//Add column sorting
if($_REQUEST['sort'] != '')
$sort = ' order by added asc ';
else
$sort = $_REQUEST['sort'];
### DEBUG
if($debugP) echo 'Advanced Search Sql<hr>'.$sql;
$error['Results'] = 'Sorry no properties found.';
### Finished Building search sql and execting #####
$sql_with_limit = $sql . $sort . $limit;
if($debugP)
echo "<hr>Property Search with Limit SQL: $sql_with_limit";
//Perform search
$searchResults = mysql_query($sql.$sql_with_limit);
### BUILD OUTPUT ####
if (isset($_GET['totalRows_p'])) {
$totalRows_p = $_GET['totalRows_p'];
} else {
if($debugP)
echo "<hr>Property with out limit SQL: $sql $sort";
$all_p = mysql_query($sql.$sort);
$totalRows_p = mysql_num_rows($all_p); //$totalRows_p = mysql_num_rows($all_p);
if($debugP)
echo "<br>Result Rows $totalRows_p";
}
$totalPages_p = ceil($totalRows_p/$maxRows_p)-1;
if($debugP)
echo "<hr>Builting Query String for Limit: ";
//Build query string
foreach($_GET as $name => $value){
if($name != "pageNum_p")
开发者_运维知识库 $queryString_p .= "&$name=$value";
}
if($debugP)
echo $queryString_p;
?>
It probably because that MySQL was unable to process your SQL statement as supplied. Try changing your mysql_query line to the following so that you get some debug information, just try below code for your query
$all_p = mysql_query($sql.$sort) or die('Query failed: ' . mysql_error() . "<br />\n$sql");
Thanx.
I think that your problem is here:
$all_p = mysql_query($sql.$sort);
$totalRows_p = mysql_num_rows($all_p);
from the message you get $all_p is not a valid resource. This might be due to an error in the query you are passing
have you tried doing this?
$all_p = mysql_query($sql.$sort);
if ($all_p !== false){
$totalRows_p = mysql_num_rows($all_p);
}
if you see no warning you have a problem with your query and you should debug that. Try to execute you query in mysql and look if any results are returned.
You're using direct assignment for $search
when you want array assignment. This means that when you go to implode it, it probably returns false(??? I've never suppressed warnings on implode. I have no idea what that does.). That is being misread when appended to $sql. You then append $sort and $limit to $sql and then prepend $sql again for good measure before calling mysql_query. You're also not checking to see if $_REQUEST['city'] and $_REQUEST['desitination'] have values.
Your final result (worse case):
select * FROM properties WHERE type= "'.$type.'" and select * FROM properties WHERE type= "'.$type.'" and order by added asc Limit 0,10
Your final result (best case):
select * FROM properties WHERE type= "'.$type.'" and city = 'Atlanta' select * FROM properties WHERE type= "'.$type.'" and city = 'Atlanta' order by added asc Limit 0,10
Add this at the top:
$search = array();
and then any time you want to append $search
:
$search[] = ' district = '.$_REQUEST['district'];
And replace this line $searchResults = mysql_query($sql.$sql_with_limit);
with:
$searchResults = mysql_query($sql_with_limit);
BTW you're begging for SQL injection here. Any time you pull a value from $_REQUEST
, you should be using mysql_real_escape_string
.
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