How to substitute a string in bash script
Note:
- Bash 3.00
How to substitute this example string 123456789, to look like 123-456-789
#!/bin/sh
# trivial example
read number;
# monotically substitute '-' into开发者_StackOverflow string after first three and dix digits
Without the use of sed
:
$ number=123456789
$ number=${number:0:3}-${number:3:3}-${number:6:3}
$ echo $number
123-456-789
phone=`echo $phone | sed 's/\(...\)\(...\)/\1-\2-/'`
one way with gawk
$ echo "123456789" |awk 'BEGIN{FS=""}{ for(i=1;i<=NF;i+=3)s=s$(i)$(i+1)$(i+2)"-";sub(/-$/,"",s);print s } '
123-456-789
$ echo "123456789abcdef" | awk 'BEGIN{FS=""}{ for(i=1;i<=NF;i+=3)s=s$(i)$(i+1)$(i+2)"-";sub(/-$/,"",s);print s } '
123-456-789-abc-def
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