In go, how do you create an interface when methods are called by *Type?
Attempting to create an interface, but methods have *Type
, not Type
receivers
APOLOGIZE: was sleepy and mis-read error messages. Thought I was being block from creating the DB interface when in reality I was mis-using it. Sorry about that... will be more careful in the future!
type Char string func (*Char) toType(v *string) interface{} { if v == nil { return (*Char)(nil) } var s string = *v ch := Char(s[0]) return &ch } func (v *Char) toRaw() *string { if v == nil { return (*string)(nil) } s := *((*string)(v)) return &s }
from here I would like an开发者_JAVA百科 interface that contains the methods toType
and toRaw
type DB interface{ toRaw() *string toType(*string) interface{} }
does not work since the function receivers are pointers. I say this because when I try to use it I get the error.k
Char does not implement DB (toRaw method requires pointer receiver)
Is there a way to create an interface from toType
and toRaw
, or do I need to backup and have the receivers be the types themselves and not pointers to types?
If you define your interface methods for the pointer type you must pass a pointer to the methods/functions expecting the interface.
I don't understand what your problem is. Yes, the way you've written it, *Char
conforms to the interface DB
and Char
doesn't. You can either
- change your code so that the methods operate on the non-pointer type
Char
directly (which will automatically also work for*Char
too) - only use
*Char
when you need something to be compatible with typeDB
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