Ajax calling PHP Function
So thanks to the response to my previous question, I've tried to make a code to e-mail me if the code is on another site.
Here is my javascript which is intended for a potential code theif to take with them to their website:
<script type="text/javascript">
var mypostrequest=new ajaxRequest()
mypostrequest.onreadystatechange=function(){
if (mypostrequest.readyState==4){
if (mypostrequest.status==200 || window.location.href.inde开发者_C百科xOf("http")==-1){
document.getElementById("result").innerHTML=mypostrequest.responseText
}
else{
alert("An error has occured making the request")
}
}
}
var url = document.domain;
var joel="www.joelhoskin.net76.net";
if (url!=joel)
{
mypostrequest.open("POST", "http://www.joelhoskin.net76.net/email.php", true)
mypostrequest.setRequestHeader("Content-type", "application/x-www-form-urlencoded")
mypostrequest.send(url)
}
</script>
and here is the php at joelhoskin.net76.net/email.php
`<?php
$url=$_POST['url'];
if(isset($url))
{
$to = 'FlexDevs@gmail.com';
$from = 'Errors@FlexDevs.com';
$subject = 'Stolen Page';
$content = $url."Site Stolen";
$result = mail($to,$subject,$content,'From: '.$from."\r\n");
die($result);
}
?>`
It isn't emailing me like it should
mypostrequest.send(url)
You do send data, but without key. Do it this way:
mypostrequest.send('url='+url)
It should make it work.
精彩评论