Launch another app from myapp without url scheme - jailbreak users are able to, so how?

i'm trying to write a small application, a "launcher" app, that comes up when i plug my phone to power supply. Now there should be a 4x4 grid with my fav app i want to load. therefore no problem.

But how to start an app from an app? I read dozens of times that is is not possible, to do it without url shemes like tel://

How are jailbreak applications able to to this? Like Activator, PluggedIn, iSheduler... 开发者_如何学PythonI have them running on my phone, and they are able to start any application, also my own, which don't have url scheme.

I tried lauchner from Erica Utilities, but it just crashed.

It is possible, but how?

Thanks for any advice Greetings Max

You can activate an app by importing these classes:

SBApplicationController  
SBUIController  
SBApplication

The SBApplicationController gets your app, the SBApplication, and then opens it using the SBUIController like so:

Class SBApplicationController=objc_getClass("SBApplicationController"); 

SBApplication *app=[[SBApplicationController sharedInstance] applicationWithDisplayIdentifier:@"com.company.yourapp"];//change the bundle identifier for whichever app you want

[[objc_getClass("SBUIController") sharedInstance] activateApplicationFromSwitcher:app];

Finally i found a solution: open - a commandline tool by Conrad Kramer: http://thecydiastore.com/app/com.conradkramer.open/