How to create/instantiate an object of 'Type' [duplicate]

This question already has answers here: How to create a new object instance from a Type (11 answers) 开发者_StackOverflow社区 Closed 9 years ago.

I want to iterate through types in an assembly and if a type is a subclass of a specified interface, I want to create an object of the type and add it to a list like so:

var tasks = new List<IScheduledTask>();

foreach (Type t in Assembly.GetExecutingAssembly().GetTypes())
{
    if (t.IsSubclassOf(typeof(IScheduledTask)))
    {
        tasks.Add(new t());
    }
}

Obviously this above does not work. How can you achieve what I am seeking?

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Activator.CreateInstance is what you're after.

var tasks = new List<IScheduledTask>();
foreach (Type t in Assembly.GetExecutingAssembly().GetTypes())
{
    if (t.IsSubclassOf(typeof(IScheduledTask)))
    {
        tasks.Add((IScheduledTask)Activator.CreateInstance(t));
    }
} 

---

Look at using the Activator.CreateInstance method:

ObjectType instance = (ObjectType)Activator.CreateInstance(objectType);

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This previous question may help Instantiate an object with a runtime-determined type

It uses Activator.CreateInstance

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Activator.CreateInstance(t);

will do the trick.

Be careful though, the class you want to instanciate must have a public constructor with no argument for it to work.