PHP pass variable to foreach loop from a mySQL result
I need to pass a开发者_开发知识库 variable to a foreach loop from a mySQL result.
So I have this code:
$GetClaim = "SELECT * FROM cR_Claimants WHERE memberID = '".$memberID."' AND ParentSubmission ='".$refNumb."'";
$resultGetClaim=mysql_query($GetClaim) or die("Error select claimants: ".mysql_error());
while($rowGetClaim = mysql_fetch_array($resultGetClaim)) {
$name = $rowGetClaim['Name'];
$city = $rowGetClaim['city'];
$region = $rowGetClaim['region'];
}
Now I need to pass the variable to the foreach
foreach($name as $k=>$v) {
echo $city;
echo $region;
etc..
}
The above code does not work. I think I cannot pass a variable from a mySQL loop. The problem is also tat every row I get from the database should be related to the specific $name. So obvioiusly one $name will have its own $city etc..
How do I achieve this?
Please help
You are not retrieving an array with all returned records, you are retrieving an array which contains a single record.
To get the next name
(the next record), you must make another call to mysql_fetch_array.
The code you present does that implicitly by assigning $rowGetClaim within a while conditional. A failed mysql_fetch_array call would return false
, which would exit the while loop.
There is absolutely no need to use the for each as you presented. Just place the echo
right after the assignment (e.g.
$region = $rowGetClaim['region'];
echo $region
Either out put directly fromt eh loop or build an array and then loop through it.
while($rowGetClaim = mysql_fetch_array($resultGetClaim)) {
echo $rowGetClaim['Name'];
echo $rowGetClaim['city'];
echo $rowGetClaim['region'];
}
OR
while($rowGetClaim = mysql_fetch_array($resultGetClaim)) {
foreach($rowGetClaim as $k => $v{
echo $v;
}
}
OR
$names = array();
while($rowGetClaim = mysql_fetch_array($resultGetClaim)) {
$names[] = $rowGetClaim;
}
foreach($names as $data){
foreach($data as $k => $v) {
echo $v;
}
}
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