how to concatenate two getElementsBy

I have a snippet of code like this:

var profileLinks = new Array();

for (var i = 0; i<searchResult.length; ++i) 
{
    var profileLink=searchResult[i].getElementsByTagName("a");
    profileLinks[i]=profileLink[0].href;
    alert(i+1+" of "+se开发者_JS百科archResult.length+" "+profileLinks[i]);
}

It seems like I should be able to make it more concise by using this:

//alternate construction (why doesn't this work?)

var searchResult = document.getElementsByClassName("f_foto").getElementsByTagName("a");

What's wrong here?

Use querySelectorAll() instead:

var searchResult = document.querySelectorAll(".f_foto a");

IE 8 supports querySelectorAll() but not getElementsByClassName(), so this should give you better compatibility too.

For full compatibility, stick to your original code or use a library like jQuery.

document.getElementsByClassName("f_foto")  

returns a selection, therefore you cannot chain functions to it. You need to specify an element directly not a whole selection, for example this would work correctly.

 document.getElementsByClassName("f_foto")[0].getElementsByTagName("a"); 

Because document.getElementsByClassName("f_foto")[0] points to an object and not to a selection of objects.

This is why we have libraries - or even modern browsers. You are looking for the css selector $('.f_foto a') in jQuery, or $$('.f_foto a') in Prototoype/Chrome

You call getElementsByTagName on a node, not an array, which is what is returned by getElementsByClassName.

I believe that getElementsByTagName can only be applied to an element node, but the result of getElementsByClassName is surely going to be a list of nodes. You'll either have to pick one ([0]?) or iterate over the collection (make sure it's not empty!).