GeneralPath curveTo
i would like to know how to define the control point, here is what i do now, but it is really not efficient and the curve is not smooth.
MyPoint pointStart = list.get(0);
path.moveTo(pointStart.getLocationX(), poi开发者_开发问答ntStart.getLocationY());
MyPoint pointEnd = list.get(list.size() - 1);
for (int i = 1; i < list.size() - 1; i++) {
MyPoint point = list.get(i);
if (i % 3 == 0) {
MyPoint controlPoint1 = list.get(i - 2);
MyPoint controlPoint2 = list.get(i - 1);
MyPoint endPoint = point;
path.curveTo(controlPoint1.getLocationX(), controlPoint1.getLocationY(), controlPoint2.getLocationX(), controlPoint2.getLocationY(), endPoint.getLocationX(), endPoint.getLocationY());
((Graphics2D) g).draw(path);
}
}
path.lineTo(pointEnd.getLocationX(), pointEnd.getLocationY());
GeneralPath.curveTo()
uses Bézier curves, for which control points are NOT supposed to be part of the curve itself, but are here to determine the inflection of the curve at is end points (as can be seen in the curve drawn on the former Wikipedia link).
It seems what you're looking for is a spline curve which intersects all provided points. Unfortunately, this type of curve doesn't seem to be supported by Java2D. But you could probably implement it, if you have some good geometry knowledge (and with the help of Wikipedia) and some time to waste.
Another way, might be (I haven't tried it though), for a given pair of points Pi & Pi+1 to join with a curve, to determine control points based on previous and next points Pi-1 and Pi+2; might be worth investigating.
This question is somewhat addressed in the following post. I came across this post first so I'm adding the link for anyone else who comes here.
How do I create a Bezier curve to represent a smoothed polyline?
The first answer in this post gives a good explanation on how to build 'good' Bezier control points. I used a similar method and got nice results ie smooth curves.
Also the final paragraph of the previous answer basically describes building a bezier spline (one of many spline curves).
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