XML syntax validation in Java [closed]

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I've been trying to figure out how开发者_如何学运维 to check the syntax of an XML file, make sure all tags are closed, there's no random characters, etc... All I care at this point is making sure there is no broken XML in the file.

I've been looking at some SO posts like these...

• Validate an XML file against local DTD file with Java

• What's the best way to validate an XML file against an XSD file?

... but I realized that I don't want to validate the structure of the XML file; I don't want to validate against an XML Schema (XSD)... I just want to check the XML syntax and determine if it is correct.

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You can check if an XML document is well-formed using the following code:

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
factory.setValidating(false);
factory.setNamespaceAware(true);

DocumentBuilder builder = factory.newDocumentBuilder();

builder.setErrorHandler(new SimpleErrorHandler());    
// the "parse" method also validates XML, will throw an exception if misformatted
Document document = builder.parse(new InputSource("document.xml"));

The SimpleErrorHandler class referred to in the above code is as follows:

public class SimpleErrorHandler implements ErrorHandler {
    public void warning(SAXParseException e) throws SAXException {
        System.out.println(e.getMessage());
    }

    public void error(SAXParseException e) throws SAXException {
        System.out.println(e.getMessage());
    }

    public void fatalError(SAXParseException e) throws SAXException {
        System.out.println(e.getMessage());
    }
}

This came from this website, which provides various methods for validating XML with Java. Note also that this method loads an entire DOM tree into memory, see comments for alternatives if you want to save on RAM.

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What you are asking is how to verify that a piece of content is well-formed XML document. This is easily done by simply letting an XML parser (try to) parse content in question -- if there are issues, parser will report an error by throwing exception. There really isn't anything more to that; so all you need is to figure out how to parse an XML document.

About the only thing to beware is that some libs that claim to be XML parsers are not really proper parsers, in that they actually might not verify things that XML parser must do (as per XML specification) -- in Java, Javolution is an example of something that does little to no checking; VTD-XML and XPP3 do some verification (but not all required checks). And at the other end of spectrum, Xerces and Woodstox check everything that specification mandates. Xerces is bundled with JDK; and most web service frameworks bundle Woodstox in addition.

Since the accepted answer already shows how to parse content into a DOM document (which starts with parsing), that might be enough. The only caveat is that this requires that you have 3-5x as much memory available as raw size of the input document. To get around this limitation you could use a streaming parser, such as Woodstox (which implements standard Stax API). If so, you would create an XMLStreamReader, and just call reader.next() as long as reader.hasNext() returns true.

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http://www.ibm.com/developerworks/xml/library/x-javaxmlvalidapi/index.html Does this help? It uses XSD which is pretty robust. Not only can you validate the documents structure, but you can supply some pretty complex rules about what type of content your nodes and attributes can contain.