How to get child location in a treeview?
I currently have a simple tree view that contains one parent node with multiple child nodes. I was wondering if there is a way to find the location of the selected node in the parent tree.
I currently have an action event on the treeview and when th开发者_Go百科e user clicks on the child it prints out the string value of the selected child. I have tried using:
int val = TreeView.SelectedItemProperty.GlobalIndex;
but it always returns 0. I have seen some examples in VB but I cant seem to get the same idea to work in C#.
You have to use the ItemContainerGenerator property of the Treeview.
http://msdn.microsoft.com/en-us/library/system.windows.controls.itemcontainergenerator.aspx
See: ContainerFromIndex and IndexFromContainer
Note that each TreeViewItem also has an ItemContainerGenerator (its an ItemsControl), so you'd have to recursively search down the tree if you have multiple levels.
I think the answer to all your treeview problems (and most ui ones) in wpf is to build a ViewModel. Anytime you start crawling the visual tree to look for elements that you are already binding to, you are doing things the hard way. Once you start using ItemsContainerGenerator you have to start worrying about a whole lot of issues you should not have to.
You are binding to a hierarchical structure. If that structure has a selected item property on each item and it is bound to the TreeViewItem selected item then you can just get the selected item in code and do everything else from there. Have a look at a similiar question here.
So i didn't find the answer i was looking for (I may of confused others with what my question was. by saying location). Anyways how I solved it was I got the string value of the child selected and compared it to my list. Thanks to those who answered!
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