Unix Awk array not printing values

This is the exact code I am running in my system with sh lookup.sh. I don't see any details within nawk block printed or written to the file abc.txt. Only I am here 0 and I am here 1 are printed. Even the printf in nawk is not working. Please help.

processbody() {
nawk '
NR == FNR {
split($0, x, "@")
country_code[x[2]] = x[1]
next
system(" echo " I am here ">>/tmp/abc.txt") 
}
{
CITIZEN_COUNTRY_NAME = "INDIA"
system(" echo " I am here 1">>/tmp/abc.txt") 
if (CITIZEN_COUNTRY_NAME in country_开发者_StackOverflowcode) {
value = country_code[CITIZEN_COUNTRY_NAME]
system(" echo " I am here 2">>/tmp/abc.txt") 
} else {
value = "null"
system(" echo " I am here 3">>/tmp/abc.txt") 
}
system(" echo " I am here 4">>/tmp/abc.txt") 
print "found " value " for country name " CITIZEN_COUNTRY_NAME  >> "/tmp/standalone.txt"
} ' /tmp/country_codes.config
echo "I am here 5" >> /tmp/abc.txt
}

# Main program starts here
echo "I am here 0" >> /tmp/abc.txt
processbody 

And my country_codes.config file:

$ cat country_codes.config
IND@INDIA
IND@INDIB
USA@USA
CAN@CANADA

That's some pretty interesting awk code. The problem is that your first condition, the NR == FNR one, is active for each record read from the first file - the country_codes.config file, but the processing action contains next so after it reads a record and splits it and saves it, it goes and reads the next record - not executing the second block of the awk script. At the end, it is done - nothing more to do, so it never prints anything.

This works sanely:

processbody() 
{   
    awk '
        {
        split($0, x, "@")
        country_code[x[2]] = x[1]
        #next
        }
    END {
        CITIZEN_COUNTRY_NAME = "INDIA"
        if (CITIZEN_COUNTRY_NAME in country_code) {
            value = country_code[CITIZEN_COUNTRY_NAME]
        } else {
            value = "null"
        }
        print "found " value " for country name " CITIZEN_COUNTRY_NAME
    } ' /tmp/country_codes.config
}   

# Main program starts here
processbody

It produces the output:

found IND for country name INDIA

As Hai Vu notes, you can use awk's intrinsic record splitting facilities to simplify life:

processbody()
{
    awk -F@ '
    { country_code[$2] = $1 }
    END {
        CITIZEN_COUNTRY_NAME = "INDIA"
        if (CITIZEN_COUNTRY_NAME in country_code) {
            value = country_code[CITIZEN_COUNTRY_NAME]
        } else {
            value = "null"
        }
        print "found " value " for country name " CITIZEN_COUNTRY_NAME
    } ' /tmp/country_codes.config
}

# Main program starts here
processbody

I don't know what you want to accomplish, but let me guess: if country is INDIA, then print the following output:

found IND for country name INDIA

If that is the case, the following code will accomplish that goal:

awk -F@ '/INDIA/ {print "found " $1 " for country name " $2 }' /tmp/country_codes.config 

The -F@ flag tells awk (or nawk) to use @ as the field separator.

@user549432 I think that you want one awk script that first reads in the country codes file and builds the associative array, and then reads in the input files (not @ delimited) and does a substitution?

if so, let's assume that /tmp/country_codes.config has:

IND@INDIA
IND@INDIB
USA@USA
CAN@CANADA

and /tmp/input_file (not @ delimited) has:

I am from INDIA
I am from INDIB
I am from CANADA

Then, we can have a nawk script like this:

nawk '

BEGIN {
        while (getline < "/tmp/country_codes.config")
        {
          split($0,x,"@")
          country_code[x[2]] = x[1]
        }
      }

  { print $1,$2,$3,country_code[$4]}

' /tmp/input_file

The output will be:

I am from IND
I am from IND
I am from CAN