Grep: Return a user message when no hits

I have ASCII files to parse that 48 hours old or more ; I can identify them like so

find . -name "FILE*TXT"  -mtime +1 -exec ls -ltas '{}' ';' 

Some files have a list of hardware errors (we test electronic components), some have none. If the file name has no errors, I still want to display a message like so

    grep ^err R*VER && echo "No error"
FILEA.TXT:err   ->USB   3910    err 
FILED.TXT:err No Error

This grep statement works but it seemingly overrides the find() statement above if I run both at the same time... How can I combine the two statements to create a report that lists the filename and error(s) like so

FILEA.TXT Button    3320    err
FILEB.TXT USB   3235    err
FILEC.TXT IR Remote 2436    err
FILED.TXT No error

Is it possible to return "No error" with the file name without error? Thanks in advance for you开发者_Go百科r help.

The -exec predicate returns false if the command returns failure.

find ... \( -exec grep ... {} \; -o -printf "%p No error\n" \) ...

A friend came up with this

find . -name "FILE*TXT" -mtime +1 -exec sh -c 'grep -H ^err "{}" || echo "{}:No error"' \;

I could not figure out how to run grep for each file ; his solution does exactly that.

Thanks for taking the time.