Memory allocation clarification

I am trying to set a negative zero to an array in two ways. I need to know how the memory will be allocated for each type.

Type 1:

double dArray=new double[2];
dArray[0]= 0;
dArray[1]=-0;

Type 2:

double dArray=new double[2];
dArray[0]=0;
dArray[1]=-dArray[0];

Can any one clarify on this.

Thanks, Lokesh.

The code doesn't compile. I think you mean

double[] dArray=new double[2];

A double is a value type and it makes no difference to its storage how you assign to a double value. The two code samples (once fixed), result in exactly the same memory layout for dArray.

It would be very much clearer to always write -0.0.

Note that Visual Studio always represents negative zero as 0.0 which does tend to shake your confidence in the existence of -0.0!

There is some relevant discussion of negative zero here: How can I test for negative zero?

I'd be interested in understanding your use case because ordinarily −0 = +0 = 0.

In any case they would both be treated as value types.