insert unbounded XML element using xslt

I did post many questions regarding inserting XML elements using XSLT, I am new to XSLT and I am learning while working on it. So thanks to everyone that helped me through.

Now, I came up with another question: so I am inserting a repeatable (unbounded) XML element so it will have the same xpath but different values for the element, when I put the xpath to match the template pattern it overrides the earlier elements that have been inserted. So is there a way to insert multiple elements into an exisiting XML using the same xpath? my input is the xpath where those elements sh开发者_如何学Goould be inserted and the elements values. For example my input is:

xpath: /root/child
element to insert: new_element
with the values: new1, new2 new3

so the output should look like:

<root>
 <child> 
   <new_element>new1</new_element>
   <new_element>new2</new_element>
   <new_element>new3</new_element>
  </child>
</root>

Thanks :)

I'm going probably to misunderstand your question, but it's hard to achieve your intents given the details in your post. I shouldn't guess here I know...anyway, are you interested in something like this...?

Example transform:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:variable name="newdata">
   <new_element>new1</new_element>
   <new_element>new2</new_element>
   <new_element>new3</new_element>
 </xsl:variable>

 <xsl:template match="node()|@*">
  <xsl:copy>
   <xsl:apply-templates select="node()|@*"/>
  </xsl:copy>
</xsl:template>

<xsl:template match="/root/child">
    <xsl:copy>
        <xsl:copy-of select="$newdata"/>
    </xsl:copy>
</xsl:template>

</xsl:stylesheet>

Given this input

<root>
 <child/> 
</root>

Returns:

<root>
   <child>
      <new_element>new1</new_element>
      <new_element>new2</new_element>
      <new_element>new3</new_element>
   </child>
</root>