What does the "Nothing to repeat" error mean when using a regex in javascript?
I'm new to Regex and I'm trying to work it into one of my new projects to see if I can learn it and add it to my repitoire of skills. However, I'm hitting a roadblock here.
I'm trying to see if the user's input has illegal characters in it by using the .search
function as so:
if (name.search("[\[\]\?\*\+\|\{\}\\\(\)\@\.\n\r]") != -1) {
...
}
However, when I try to execute the function this line is contained it, it throws the following error for that specific line:
Uncaught SyntaxError: Invalid regular expression: /[[]?*+|{}\()@.
]/: Nothing to repeat
I can't for the life of me see what's wr开发者_StackOverflow中文版ong with my code. Can anyone point me in the right direction?
You need to double the backslashes used to escape the regular expression special characters. However, as @Bohemian points out, most of those backslashes aren't needed. Unfortunately, his answer suffers from the same problem as yours. What you actually want is:
The backslash is being interpreted by the code that reads the string, rather than passed to the regular expression parser. You want:
"[\\[\\]?*+|{}\\\\()@.\n\r]"
Note the quadrupled backslash. That is definitely needed. The string passed to the regular expression compiler is then identical to @Bohemian's string, and works correctly.
Building off of @Bohemian, I think the easiest approach would be to just use a regex literal, e.g.:
if (name.search(/[\[\]?*+|{}\\()@.\n\r]/) != -1) {
// ... stuff ...
}
Regex literals are nice because you don't have to escape the escape character, and some IDE's will highlight invalid regex (very helpful for me as I constantly screw them up).
For Google travelers: this stupidly unhelpful error message is also presented when you make a typo and double up the +
regex operator:
Okay:
\w+
Not okay:
\w++
Firstly, in a character class [...]
most characters don't need escaping - they are just literals.
So, your regex should be:
"[\[\]?*+|{}\\()@.\n\r]"
This compiles for me.
Well, in my case I had to test a Phone Number with the help of regex, and I was getting the same error,
Invalid regular expression: /+923[0-9]{2}-(?!1234567)(?!1111111)(?!7654321)[0-9]{7}/: Nothing to repeat'
So, what was the error in my case was that +
operator after the /
in the start of the regex. So enclosing the +
operator with square brackets [+]
, and again sending the request, worked like a charm.
Following will work:
/[+]923[0-9]{2}-(?!1234567)(?!1111111)(?!7654321)[0-9]{7}/
This answer may be helpful for those, who got the same type of error, but their chances of getting the error from this point of view, as mine! Cheers :)
for example I faced this in express node.js when trying to create route for paths not starting with /internal
app.get(`\/(?!internal).*`, (req, res)=>{
and after long trying it just worked when passing it as a RegExp Object using new RegExp()
app.get(new RegExp("\/(?!internal).*"), (req, res)=>{
this may help if you are getting this common issue in routing
This can also happen if you begin a regex with ?
.
?
may function as a quantifier -- so ?
may expect something else to come before it, thus the "nothing to repeat" error. Nothing preceded it in the regex string so it didn't get to quantify anything; there was nothing to repeat / nothing to quantify.
?
also has another role -- if the ?
is preceded by (
it may indicate the beginning of a lookaround assertion or some other special construct. See example below.
If one forgets to write the ()
parentheses around the following lookbehind assertion ?<=x
, this will cause the OP's error:
Incorrect: const xThenFive = /?<=x5/;
Correct:
const xThenFive = /(?<=x)5/;
This /(?<=x)5/
is a positive lookbehind: we're looking for a 5 that is preceded by an x
e.g. it would match the 5
in x563
but not the 5
in x652
.
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