What is the proper way to test a Bash function's return value?
I would like to test a Bash function's return value in an if statement like this:
if [[ func arg ]] ; then …
But I get error 开发者_StackOverflowmessages like: conditional binary operator expected.
What is the right way to do this?
Is it the following?
if [[ $(func arg) ]] ; then ...
If it was the exit code and not the result, you could just use
if func arg; then ...
If you cannot make the function return a proper exit code (with return N
), and you have to use string results, use Alex Gitelman's answer.
$ help if
:
if: if COMMANDS; then COMMANDS; [ elif COMMANDS; then COMMANDS; ]… [ else COMMANDS; ] fi
Execute commands based on conditional.
The
if COMMANDS
list is executed. If its exit status is zero, then thethen COMMANDS
list is executed. Otherwise, eachelif COMMANDS
list is executed in turn, and if its exit status is zero, the correspondingthen COMMANDS
list is executed and the if command completes. Otherwise, theelse COMMANDS
list is executed, if present. The exit status of the entire construct is the exit status of the last command executed, or zero if no condition tested true.Exit Status:
Returns the status of the last command executed.
If you need to test two conditions, one being the exit status of function/command and the other e.g. value of variable, use this:
if func arg && [[ $foo -eq 1 ]]; then echo TRUE; else echo FALSE; fi
This error seems to be produced if the function returns more than one word.
For example, 1 2
.
Just quote it:
"$(func arg)"
Sample:
$ if [[ 1 2 ]] ; then echo 1 ; fi
-bash: conditional binary operator expected
-bash: syntax error near `2'
$ if [[ "1 2" ]] ; then echo 1 ; fi
1
And if you compare 0 vs non 0, just use
if [[ "$(func arg)" != "0" ]]
On a related note, if the function returns a variety of exit codes instead of true/false, then:
func args; ec=$? # call function and grab the exit code
# it is better to have them on the same line so that a future addition of a command
# before the case statement wouldn't break the logic
case $ec in
value1) # commands
;;
value2) # commands
;;
*) # commands
;;
esac
select
provides a lot of help here.
PS3="What's your choice? (^D to stop choosing): "
select mainmenuinput in updatesystem installsamba installvsftpd installwebmin configuresambaforactivedirectory quitprogram; do
case "$mainmenuinput" in
"updatesystem")
echo "Update System..."
;;
"installsamba")
echo "Installing Samba..."
;;
#echo And so forth...
esac
done
echo Done
For help with select
, consult man bash
and search for 'select'. Providing no input will repeat the menu.
select name [ in word ] ; do list ; done
The list of words following in is expanded, generating a list of items. The set of expanded words is printed on the standard error, each preceded by a number. If the in word is omitted, the
positional parameters are printed (see PARAMETERS below). The PS3 prompt is then displayed and a line read from the standard input. If the line consists of a number corresponding to one of
the displayed words, then the value of name is set to that word. If the line is empty, the words and prompt are displayed again. If EOF is read, the command completes. Any other value read
causes name to be set to null. The line read is saved in the variable REPLY. The list is executed after each selection until a break command is executed. The exit status of select is the
exit status of the last command executed in list, or zero if no commands were executed.
Sample Output:
[rinzler ~] $ ./test.sh
1) updatesystem 4) installwebmin
2) installsamba 5) configuresambaforactivedirectory
3) installvsftpd 6) quitprogram
What's your choice? (^D to stop choosing): 1
Update System...
What's your choice? (^D to stop choosing): 2
Installing Samba...
What's your choice? (^D to stop choosing):
1) updatesystem 4) installwebmin
2) installsamba 5) configuresambaforactivedirectory
3) installvsftpd 6) quitprogram
What's your choice? (^D to stop choosing):
Done
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