Index manipulation of array in C
Begining with an ordered array
开发者_StackOverflow社区 [1, 2, 3, 4, 5, 6, 8, 9, 10]
How would be the way to get every iteration the following results?
1 2 3 4 5 6 7 8 9 10
1 3 4 5 6 7 8 9 10 2
1 4 5 6 7 8 9 10 2 3
1 5 6 7 8 9 10 2 3 4
1 6 7 8 9 10 2 3 4 5
1 7 8 9 10 2 3 4 5 6
1 8 9 10 2 3 4 5 6 7
1 9 10 2 3 4 5 6 7 8
1 10 2 3 4 5 6 7 8 9
#include <stdio.h>
#define MAX 10
int a[MAX], i,j,cnt=2;
main (){
for (i=0; i<MAX; i++){
a[i]= i+1;
}
for (i=0; i<MAX; i++) {
printf ("%d ", a[i]);
}
printf ("\n");
for (j=0; j < MAX-2;j++){
a[0]=1;
for (i=1; i < MAX-1; i++){
if (a[i]%MAX != 0){
a[i]= a[i] + 1;
}else{
if (a[i]==10) {
//printf ("a[%d]: %d \t ** %d\n", i , a[i] ,cnt);
//a[i-1]= i;
a[i] = cnt;
}
}
}
for (i=0; i<MAX; i++) {
printf ("%d ", a[i]);
}
printf ("\n");
}
}
Now I almost get it but the last column is not right, What should I do?
1 2 3 4 5 6 7 8 9 10
1 3 4 5 6 7 8 9 10 10
1 4 5 6 7 8 9 10 2 10
1 5 6 7 8 9 10 2 3 10
1 6 7 8 9 10 2 3 4 10
1 7 8 9 10 2 3 4 5 10
1 8 9 10 2 3 4 5 6 10
1 9 10 2 3 4 5 6 7 10
1 10 2 3 4 5 6 7 8 10
C arrays are indexed from 0. So when you access elements from 1 to MAX, you are running off the end of the array.
Have your loops go from 0 to MAX-1. Customary way to write it is
for (i=0 ; i < MAX ; ++i)
...so anybody reading your code can immediately prove that the array index never equals MAX.
Well, at a minimum, arrays in C are zero based so you are writing past the end of the array. For an array declared int foo[MAX]
valid elements are from foo[0]…foo[MAX-1]
Specifically a[MAX] might well reference the memory location that the variable i uses, causing the loop to reset when it attempt to overwrite a[MAX].
Either shift everything down by one, or declare your array MAX+1 and ignore the zero bit.
Oh, and you should not need to set a[1]=1; every time.
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