开发者

How do I remove a wrapper from a JSON Object?

I have a JSON object with a wrapper which contains information about the service it came from. Before parsing the object I really care about I would like to take off the wrapp开发者_如何学Pythoner and then just parse the object.

How do I turn this JSON object:

{"object":{"id_object": 1, "description": "Black" }, "origin":"colors"}

Into this:

{"id_object": 1, "description": "Black"}

I am using GSON as JSON parser, but if any other will give me the functionallity, I can change the library.

Thanks in advance.


Since the whole thing is a blob of json, it doesn't make sense to 'unwrap it.' Just parse the whole thing, and and grab the value of the 'object' key, and go along from there.


Super hacky solution:

private class Holder{
    private IdHolder object;
    private String origin;

    public IdHolder getObject() {
        return object;
    }
    public String getOrigin() {
        return origin;
    }

    private class IdHolder{
        private int id_object;
        private String description;
    }
}


    Holder holder = gson.fromJson("{\"object\":{\"id_object\": 1, \"description\": \"Black\" }, \"origin\":\"colors\"}", Holder.class);
    System.out.println(gson.toJson(holder.getObject()));

Would recommend @bmargulies answer though, that is the right thing to do.

0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜