TinyMCE: Detecting onLeave()
I am trying to detect when the user has left the tinyMCE editor window but I am unable to do so. Here is the code that i think should work (but isnt):
$('.mceEditor').blur(function(){
// I would expect this to f开发者_C百科ire when the user leaves the
// tinyMCE editor, but it never seems to fire
});
I've also tried:
$('*')
.not('.mceEditor, .mceEditor *')
.click(function(){
// I would expect this to fire when anything but the tinyMCE editor
// has been clicked, but it seems to fire at every click
});
Neither methods are working and ive been at this for hours. Any help would be greatly apreciated.
Thanks, Simon
PS: I am using the jquery plugin version, found here: http://tinymce.moxiecode.com/examples/example_23.php
I guess this should work
tinyMCE.dom.Event.add(tinyMCE.getInstanceById("editor-id").getWin(), "blur", function(){
// Blur operations
});
Looks like tinymce is being plugged in with an iframe. In that case you would have to access the iframe's DOM, something like this might work.
$("#content_ifr").contents().find('#tinymce');
Where content_ifr is the ID of the iframe and #tinymce seems to be the tag that encloses the content. Use firebug and poke around to see.
TinyMCE creates editor as an iframe inside a wrapper SPAN element. you can use SPAN element 'onfocusout' event.
Ex: if textarea element id is 'content', TinyMCE creates a SPAN with element id 'content_parent'.
$("#content_parent")[0].onfocusout =function(){alert('mouse out');};
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