Better way of calculating sum of even ints
I'm trying to write a programme to prompt the user to input an int
which is above or equal 2. From this input the programme must then 开发者_高级运维calculate and print the sum of all the even integers between 2 and the entered int
. It must also produce an error message if the inputted int
is below 2. I've made a programme for it that works but am just wondering if you guys could find a better way of doing it? I'm sure there is but I can't quite seem to find a way that works!
Here's what I did:
import java.util.Scanner;
public class EvenSum {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Enter an integer which is above 2.");
int number = scan.nextInt();
int divnum = number / 2;
int divnum2 = divnum + 1;
int sumofeven = divnum * divnum2;
if(number >= 2)
System.out.println("The sum of the even integers between the number is "+
sumofeven);
else
System.out.println("Invalid number entered.");
}
}
Note: do not use this example in a real context, it's not effective. It just shows a more clean way of doing it.
// Check the input.
if (number >= 2)
System.out.println(sum(number));
}
// Will find the sum if the number is greater than 2.
int sum(int n) {
return n == 2 ? n - 2 : n % 2 == 0 ? n + sum(n - 2) : sum(n - 1);
}
Hope this helps. Oh, by the way, the method sum
adds the numbers recursively.
Sorry, but I had to edit the answer a bit. There might still be room for improvement.
Why do it with a loop? You can actually calculate it out. Let X be the number they choose. Let N be the largest even number <= X. (N^2+2*N)/4 will be your answer.
Edit: just saw the answer above me. He is right. I gave the function I suppose.
Why use a loop at all? You are computing the sum of:
2 + 4 + ... n, where n is a positive even number.
This is a very simple arithmetic progression.
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Enter an integer which is above 2.");
int number = scan.nextInt();
if (number >= 2) {
int sumofeven = 0;
for (int i = 2; i <= number; i += 2) {
sumofeven += i;
}
System.out.println("The sum of the even integers between the number is " + sumofeven);
} else {
System.out.println("Invalid number entered.");
}
}
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