Regex for 1-10 in javascript for validation
What wo开发者_StackOverflow中文版uld be the regex for numbers ranging 1-10 and 1-5? Please help this troubled soul.
You could achive that with easy number checks in javascript:
// Convert input to integer just to be sure
mynum = parseInt(mynum, 10);
// Check number-range
if(mynum >= 1 && mynum <=10)
and
if(mynum >= 1 && mynum <=5)
If you really want to use regex:
/^([1-9]|10)$/
and
/^[1-5]$/
UPDATE:
- Fixed the first regex to correctly match the string boundings
- Added parseInt to the first example to ensure correct number-checks
This is not a good use of Regular Expressions.
Use simple conditions:
if (x > 0 && x < 6) {
// x is 1 - 5
}
if (x > 0 && x < 10) {
// x is 1 - 10
}
For 1-5 you only need to enclose it as character class:
/^[1-5]$/
For 1-10 you'd just need an additional alternative:
/^([1-9]|10)$/
Is there a reason you want to use regular expressions?
/([1-9]|10)/
Use numeric comparison. The following Number extension can check if a number falls between 2 values:
Number.prototype.between =
function(lower,upper, includeBoundaries){
lower = Number(lower);
upper = Number(upper);
noCando = isNaN(lower) ||
isNaN(upper) ||
lower>=upper;
if ( noCando ) {
throw 'wrong arguments or out of range';
}
return includeBoundaries
? this >= lower && this <= upper
: this > lower && this < upper
};
// usage:
(12).between(1,12); /=> false
(12).between(1,12,true); /=> true
(12).between(0,15,true); /=> true
(0).between(-5,1); //=> true
The function converts the parameters to Number because 0 can evaluate to a boolean in javascript, to be able to check if the paramaters are real number values and to be able to check if lower is not greater than/equal to upper. In those cases an error is thrown.
The includeBoundaries
parameter also checks if a Number is equal to lower or upper, if it's not supplied, the function returns a real 'between'-check.
For 1-10 it can be
/^([1-9]|10)$/
and for 1-5 simply
/^[1-5]$/
The answer would be
/^([1-9]|10)$/
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