AJAX + jQuery variables do not pass to PHP
I am trying to do something very simple: Pass 2 text variables to a php script and insert them i开发者_如何学编程nto a MySQL db. For some reason however I can't get the variables to pass (so I just get empty records in my DB).
function ajaxCall(){
$.ajax({
type: "GET",
url: "http://www.*.be/bubblingAjax.php",
cache: false,
data: "colour="+colour+"&size="+size,
dataType: "html",
success: onSuccess
});
return false;
};
And the PHP:
<?php
try
{
$connection = mysql_connect("#");
mysql_select_db("#");
$colour = mysql_real_escape_string($_GET['colour']);
$size = mysql_real_escape_string($_GET['size']);
mysql_query("INSERT INTO bubble (colour, size) VALUES ('$colour', '$size')");
mysql_close($connection);
echo "SUCCESS";
echo $colour;
echo $size;
}
catch(Exception $e)
{
echo $e->getMessage();
}
?>
Anyone willing to take a quick look at it and point out my -probably obvious- mistake? It's been driving me nuts for over a day.
This has to work:
<script type="text/javascript">
$(document).ready(function() {
//you can wrap the code into an event, e.g click()
var colour=...
var size=...
$.post("http://www.website.com/bubblingajax.php", { colour: colour, size: size },
function(data) {
alert("Respond: " + data);
});
});
</script>
and the PHP (only changed get to post)
<?php
try
{
$connection = mysql_connect("#");
mysql_select_db("#");
$colour = mysql_real_escape_string($_POST['colour']);
$size = mysql_real_escape_string($_POST['size']);
mysql_query("INSERT INTO bubble (colour, size) VALUES ('$colour', '$size')");
mysql_close($connection);
echo "SUCCESS";
echo $colour;
echo $size;
}
catch(Exception $e)
{
echo $e->getMessage();
}
?>
Also to debug, I would suggest using firebug or chrome's build in inspect tools.
The "data" parameters are sent as POST varaiables rather than GET variables. Try $_POST in the PHP
TEST THIS IN a test.php file (name matters):
<?PHP
if(isset($_POST['user_name']))
{
$post_output=
'Hello '.strtoupper($_POST['user_name']).' from '.strtoupper($_POST['user_city']).'!
This is an other random:'.rand(23,46).'.
The previous random is still alive!
I guess you can insert these 2 values
in the database on your own now, don\'t you?!';
$get_output=
'
___________________________________________
Well if you insist you can keep using get on parallel
This is what $_GET says:
'.strtoupper($_GET['getMessage']).'
And finally you can avoid post at all, to do that:
1.Use get instead of post inside the insertToDB function
2.Use send(null) instead of send(params)
3.Don\'t send the headers
HOWEVER I LIKE POST!';
echo $post_output;
print $get_output;
exit;
}
?>
<html>
<head>
<script language="javascript" type="text/javascript" >
<!--
var request = false;
try {
request = new XMLHttpRequest();
} catch (trymicrosoft) {
try {
request = new ActiveXObject("Msxml2.XMLHTTP");
} catch (othermicrosoft) {
try {
request = new ActiveXObject("Microsoft.XMLHTTP");
} catch (failed) {
request = false;
}
}
}
if (!request)
alert("Error initializing XMLHttpRequest!");
function insertToDB()
{
var url = "test.php?getMessage=Hi%20There!%20Use%20me%20if%20you%20like..";
var params = "user_name=" + (document.getElementById("user_name").value)+
"&user_city="+(document.getElementById("user_city").value);
request.open("POST", url, true);
request.setRequestHeader("Content-type", "application/x-www-form-urlencoded;charset=utf-8");
request.setRequestHeader("Content-length", params.length);
request.setRequestHeader("Connection", "close");
request.onreadystatechange = updatePage;
request.send(params);
}////////////////////
//You're looking for a status code of 200 which simply means okay.
function updatePage() {
if (request.readyState == 4) {
if (request.status == 200)
{
//alert(decodeURIComponent(request.responseText));
alert(request.responseText);
}
else{
//alert("status is " + request.status);
}
}
}
// -->
</script>
</head>
<html>
<body>
This is a random:<?PHP echo rand(1,23);?><br>
<input type="text" name="name" value="your name here" size=80 id='user_name' ><br>
<input type="text" name="city" value="your city goes here" size=80 id='user_city' ><br>
<input type="submit" name="bttn" value="Go" onClick="insertToDB( );" >
</body>
</html>
running on a mobile phone
Well I don't know if my script above will do in a mobile phone, it needs Javascript enabled!
加载中,请稍侯......
精彩评论